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The condition if two circles of equal radii cut orthoganlly |
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Answer» TWO circles with equal RADIUS pass through CENTRE of each other as shown in FIGURE. If radius = r, the area of the overlapping region would be:   Circle.jpg (14.68 KiB) Viewed 27767 times A: 2π r 2 − 3 √ 2 2πr2−32 B: 2π r 2 − π 8 2πr2−π8 C: r 2 ( 4π 3 − 3 √ 4 ) R2(4π3−34) D: r 2 ( π 3 − 2 √ ) r2(π3−2) E: r 2 ( 2π 3 − 3 √ 2 ) r2(2π3−32) |
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