The concentration of NH_4OH in 0.18 M aqueous ammonium acetate solutio – InterviewSolution

1.	The concentration of NH_4OH in 0.18 M aqueous ammonium acetate solution will be \lbrack Given: K_a(CH_3COOH)=K_b(NH_4OH)=1.8×10^{-5}\rbrack (1) 10^{-3}M (2) 10^{-4}M (3) 4×10^{-3}M (4) 6×10^{-5 }M
Answer» The concentration of NH_4OH in 0.18 M aqueous ammonium acetate solution will be \lbrack Given: K_a(CH_3COOH)=K_b(NH_4OH)=1.8×10^{-5}\rbrack (1) 10^{-3}M (2) 10^{-4}M (3) 4×10^{-3}M (4) 6×10^{-5 }M

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