1.

The concentration of [H^+] and concentration of [OH^(-) ] of a 0.1 aqueous solution of 2% ionised weak acid is ionic product of water = 1 xx10^(-14)]

Answer»

`2 xx 10^(-3)`M and` 5 xx 10^(-12)M`
`1 xx 10^(-3)M and5 xx 10^(-12) M`
`0.02 xx 10^(-3)M and5 xx 10^(-11) M`
`3 xx 10^(-2)M and4 xx 10^(-13) M`

Solution :`[H^+] = C alpha= 0.1 xx 0.02= 2 xx 10^(-3)M`
( Asdegreeof dissociation=2 % = 0.02)
hence ` [OH^-]= (10^(14))/(2 xx 10^(-3)) =5XX 10^(-12) M`


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