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The concentration of H_(2)SO_(4) in a bottle labelled ''conc. Sulphuric acid '' is 18 M. The solution has a density of 1.84gcm^(-3). What is the mole fraction and weight percentage of H_(2)SO_(4) in this solution? |
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Answer» Solution :`"Conc. = 18 mol L"^(1)`. SOLUTE = 18 moles `=18xx98g=1764g`, Solution = 1000 `cm^(3)` = 1840 g. Solvent = `1840 - 1764 = 76 g` `"Mole FRACTION of "H_(2)SO_(4)=(18)/(76//18+18)=0.81",WEIGHT"%=(1764)/(1840)xx1000=95.87.` |
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