1.

The concentration of H_(2)SO_(4) in a botal labelled ''conc. Sulphuric acid'' is 18 M. The solution has a density of "1.84 g cm"^(-3). What is the mole fraction and weight percentage of H_(2)SO_(4) in this solution?

Answer»


Solution :`"Conc. = 18 MOL L"^(-1)." Solute = 18 moles "=18xx98 g = 1764g,"Solution "=100cm^(3)=1840g.`
`"Solvent "=1840-1764 = 76g`
`"Mole FRACTION of "H_(2)SO_(4)=(18)/(76//18+18)=0.81" ,Weight "%=(1764)/(1840)xx1000=95.87.`


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