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The concentration of an organic compound in chloroform is 6.15" g per "100" mL" of the solution. A portion of this solution in a 5 cm polarimeter tube causes an observed rotation of -1.2^(@). What is the specific rotation of the compound ? |
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Answer» Solution :Specific ROTATION `=(100xxalpha)/(lxxc)=(100xx(-1.2))/(0.5xx6.15)=-39^(@)(L=5" cm "=0.5" dm")` `ALPHA`= angle of rotation l = length of the tube in dm c = concentration of the solution in `g//100` ML |
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