1.

The concentration of Ag^(+) ion in a given saturated solution of AgCl at 25^(@)C is 1.06xx10^(-5)g ion per litre. Thus, the solubility product of AgCl is :

Answer»

`0.353xx10^(-10)`
`0.530xx10^(-10)`
`1.12xx10^(-10)`
`2.12xx10^(-10)`

Solution :`K_(sp)=[AG^(+)][CL^(-)]`
`[Ag^(+)]=1.06xx10^(-5)`
and `[Cl^(-)]=1.06xx10^(-5)`
`K_(sp)=(1.06xx10^(-5))xx(1.06xx10^(-5))`
`=1.12xx10^(-10)`


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