1.

The concentration of a reactant X decreases from 0.1 M to 0.025 M in 40 minutes. If the reaction follows I order kinetics, the rate of the reaction when the concentration of X is 0.01 M will be

Answer»

`1.73xx10^(-4)"M min"^(-1)`
`3.47xx10^(-4)"M min"^(-1)`
`3.47xx10^(-5)"M min"^(-1)`
`1.73xx10^(-5)"M min"^(-1)`

Solution :`K=(2.303)/(t)"log"(A_(0))/(A)=(2.303)/(40)"log"(0.1)/(0.005)`
`=(2.303)/(40)log 20 = 0.075`
Rate of the reaction when the concentration of X is 0.01 M will be
`0.075xx0.01=7.5xx10^(-4)M min^(-1)`.
Note : No OPTION is correct in the GIVEN question.


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