1.

The concentration of a reactant changes from 0.03 M to 0.02 M in 25 minutes . The average rate of reaction using time in seconds is :

Answer»

`0.4xx10^(-3) "mol L"^(-1) s^(-1)`
`0.024 "mol" L^(-1)s^(-1)`
`0.24 "mol " L^(-1)s^(-1)`
`0.66xx10^(-4) "mol"L^(-1) s^(-1)` .

Solution :(D) Rate `=-(DELTA[R])/(Deltat)=(-(0.02-0.-03))/(24"min")`
`=0.4 xx10^(-3) "mol L"^(-1) min^(-1)`
`=0.4xx10^(-3) "mol L"L^(-1) min^(-1) `min /60 s
`=0.66 xx10^(-4) "mol L"^(-1) s^(-1)`


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