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The compressibilty factor for a real gas at high pressure is:A. `1 + (RT)/(Pb)`B. `1`C. `1 + (Pb)/(RT)`D. `1 - (Pb)/(RT)` |
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Answer» Correct Answer - C For 1 mol gas `(P+ (a)/(V^(2))) (V - b) = RT` Pressure correction can be neglected at high pressure. Thus, `P (V - b) = RT` `PV = Pb + RT` `(PV)/(RT) = 1 + (Pb)/(RT)` `Z = 1 + (Pb)/(RT)` |
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