1.

The compressibility factor (Z) of one mole of a va der Waals gas of negligible a value is

Answer»

1
`(bP)/(RT)`
`1+(bP)/(RT)`
`1-(bP)/(RT)`

Solution :As PER the vander Waals equation
`(P+a/(V^(2)))(V-b)=RT`
If a is negligible then `a/(V^(2))~~0`
`:.P(V-b)=RTimpliesPV-PB=RT`
`IMPLIES(PV)/(RT)-(Pb)/(Rt)=1impliesZ=1+(Pb)/(RT)`
(Z, COMPRESSIBILITY factor `=(PV)/(RT)`)


Discussion

No Comment Found