1.

The compressibility factor for definite amount of vander walls gas at 0^(@)C and 100 atm is found to be 0.5. Assuming the volume of gas molecules negligible the vander Waal's constant 'a' for gas in "litre"^(2)" mol"^(-2) atm is :

Answer»

1.256
0.256
2.256
10.0256

Solution :`Z=(PV)/(nRT) =0.5`
`(P+(n^(2)a)/(V^(2))(V-nb)=nRT)`
`RARR (P+(n^(2)a)/(V^(2))(V) =nRT` (b is negligible)
`therefore PV^(2) -nRTV +n^(2)a=0`
`V =(nRT pm SQRT(n^(2)R^(2)T^(2)-4n^(2)aP))/(2P)`
Since, V is constant at given P and T THUS discriminant is zero
`therefore n^(2)R^(2)T^(2)=4n^(2) aP`
`therefore


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