1.

The compound (A) is:

Answer»

a.ACIDIC `KMnO_(4)`
b.`KOBr//H_(3)O^(o+)`
c.`SeO_(2)//MeCOOH`
d.Jones reagent

Solution :`(a)`, acidic `KMnO_(4)` would oxidise both the `(C=C)` bond and keto GROUP. In `(b), KOBr` (Haloform reaction) would convert the `(-overset(O)overset(||)(C )-Me)` group to the `(O^(ɵ)-overset(O)overset(||)(C )-)` group, without affecting the `(C=C)` bond.

In `(c ), SeO_(2)//MeCOOH` would oxidise the active methyl group to `(-CHO)` group.
In `(d)`, Jones reagent `(H_(2)CrO_(4) + "aqueous acetone")` will not react, so the answer is `(b)`.


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