The complex ion [Ni(NH_(3))_(4)]^(2+) on treatment with conc. HCl gives two compounds (A) and (B) having the formula [Ni(NH_(3))_(2)Cl_(2)]. Compound (A) can be converted into compound (B) by boiling with dilute HCl. The solution of (A) reacts with oxalic acid to form [Ni(NH_(3))_(2)(C_(2)O_(4))] while solution of (B) does not react with oxalic acid. Identify (A) and (B) and also show their geometry.

The complex ion [Ni(NH_(3))_(4)]^(2+) on treatment with conc. HCl give

1.	The complex ion [Ni(NH_(3))_(4)]^(2+) on treatment with conc. HCl gives two compounds (A) and (B) having the formula [Ni(NH_(3))_(2)Cl_(2)]. Compound (A) can be converted into compound (B) by boiling with dilute HCl. The solution of (A) reacts with oxalic acid to form [Ni(NH_(3))_(2)(C_(2)O_(4))] while solution of (B) does not react with oxalic acid. Identify (A) and (B) and also show their geometry.
Answer» Solution :`[Ni(NH_(3))_(4)]^(2+)+2HClrarrunderset((A) and (B))([Ni(NH_(3))_(2)Cl_(2)])+2 NH_(3)` COMPOUND (A) is a cis-isomer which can easily form a chelate ring with the oxalate LIGAND Both compound (A) and (B) are square planar and compound A (cis-form) can be CONVERTED into compound B (trans-form) by boiling with dilute HCL.