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The complex [Fe(CN)6]4− absorbs a radiation of 356.40 nm. The pairing energy of the complex is 230 kJ/mol. Then what is the magnitude of the total crystal field splitting energy (in kJ/mol) of the complex? (Given, Plank constant=6.6×10−34Js,NA=6×1023,c=3.0×108 m/s) |
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Answer» The complex [Fe(CN)6]4− absorbs a radiation of 356.40 nm. The pairing energy of the complex is 230 kJ/mol. Then what is the magnitude of the total crystal field splitting energy (in kJ/mol) of the complex? (Given, Plank constant=6.6×10−34Js,NA=6×1023,c=3.0×108 m/s) |
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