The common tangent between the curves x2+y2=1 and y2=4(x−2), passing – InterviewSolution

1.	The common tangent between the curves x2+y2=1 and y2=4(x−2), passing through (x1,y1) on y2=4(x−2) satisfies ax21−9x1+b=0. Then a+b is equal to
Answer» The common tangent between the curves $x^{2} + y^{2} = 1$ and $y^{2} = 4 (x - 2)$ , passing through $(x_{1}, y_{1})$ on $y^{2} = 4 (x - 2)$ satisfies $a x_{1}^{2} - 9 x_{1} + b = 0$ . Then $a + b$ is equal to

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