The combined equation of two sides of a triangle is x2−3y2−2xy+8y−4=0. The third side, which is variable always passes through the point (−5,−1). If the range of values of the slope of the third line such that the origin is an interior point of the triangle is (a,b), then the value of (a+1b) is

The combined equation of two sides of a triangle is x2−3y2−2xy+8y�

1.	The combined equation of two sides of a triangle is x2−3y2−2xy+8y−4=0. The third side, which is variable always passes through the point (−5,−1). If the range of values of the slope of the third line such that the origin is an interior point of the triangle is (a,b), then the value of (a+1b) is
Answer» The combined equation of two sides of a triangle is $x^{2} - 3 y^{2} - 2 x y + 8 y - 4 = 0.$ The third side, which is variable always passes through the point $(- 5, - 1)$ . If the range of values of the slope of the third line such that the origin is an interior point of the triangle is $(a, b)$ , then the value of $(a + \frac{1}{b})$ is