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The coefficient of x in the eq iswas wrongly written as 17 in the place of 13 and the roots formed were -2 and -15. The roots of the correct eq. are ?Hint - we can do it by product and sum of roots, but I m unable to to...plz helpNo spamming |
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Answer» <P>Answer: x = -3 or x = -10 Step-by-step explanation: GIVEN => coefficient of x² = 1 coefficient of x = 17 ( taken WRONGLY ) CONSTANT = q roots of EQUATION = - 2 , - 15 => we know , product of roots = constant/coefficient of x² => -2 × -15 = q / 1 => 30 = q now , the equation becomes => x² + 13 x + 30 = 0
(given that , correct value of p = 13 ) => x² + 13 x + 30 = 0 => x² + 10x + 3x + 30 = 0 => x ( x + 10 ) + 3 ( x + 10 ) = 0 => ( x + 10 ) ( x + 3 ) = 0 so , EITHER ( x + 10 ) = 0 => x = -10 or ( x + 3 ) = 0 => x = -3 |
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