1.

The coach of cricket team buys 7 bats and 6 balls for rupees 3,800.later she buys 3 bats and 5 balls for rupees 1750 . find the cost of each ball and each ball. ​

Answer»

Step-by-step explanation:

Let cost of each bat = Rs x

Cost of each ball = Rs y

Given that coach of a CRICKET team buys 7 BATS and 6 balls for Rs 3800.

So that 7x + 6y = 3800

6y = 3800 – 7x

Divide by 6 we get

y = (3800 – 7x) /6 … (1)

Given that she buys 3 bats and 5 balls for Rs 1750.so that

3x + 5y = 1750

Plug the value of y

3x + 5 ((3800 – 7x) /6) = 1750

Multiply by 6 we get

18 x + 19000 – 35 x = 10500

-17X =10500 - 19000

-17x = -8500

x = - 8500 / - 17

x = 500

Plug this value in equation first we get

y = ( 3800 – 7 * 500) / 6

y = 300/6

y = 50

Hence cost of each bat = Rs 500 and cost of each balls is Rs 50


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