The coach of a cricket team buys 7 bats and 6 balls for Rs 3800. Later

1.	The coach of a cricket team buys 7 bats and 6 balls for Rs 3800. Later, he buys 3 bats and 5 balls for Rs 1750. Find the cost of each bat and each ball.
Answer» Let the cost of each bat be ‘a’ and each ball be ‘b’. Given, coach of a cricket team buys 7 bats and 6 balls for Rs 3800. Later, He buys 3 bats and 5 balls for Rs 1750 ⇒ 7a + 6b = 3800 ---- (1) and 3a + 5b = 1750 ---- (2) Multiplying eq1 by 3 and eq2 by 7 and subtracting eq2 from eq1. ⇒ 3(7a + 6b) - 7(3a + 5b) = 3(3800) - 7(1750) ⇒ 21a + 18b – 21a – 35b = 11400 – 12250 ⇒ -17b = - 850 ⇒ 17b = 850 ⇒ b = 50 Putting this in eq 1, we get 7a + 6(50) = 3800 ⇒ 7a + 300 = 3800 ⇒ 7a = 3500 ⇒ a = 500 Hence, Each bat cost a = 500 Rupees and Each ball costs b = 50 Rupees.

The coach of a cricket team buys 7 bats and 6 balls for Rs 3800. Later, he buys 3 bats and 5 balls for Rs 1750. Find the cost of each bat and each ball.

Answer»

Let the cost of each bat be ‘a’ and each ball be ‘b’.

Given, coach of a cricket team buys 7 bats and 6 balls for Rs 3800.

Later,

He buys 3 bats and 5 balls for Rs 1750

⇒ 7a + 6b = 3800 ---- (1)

and 3a + 5b = 1750 ---- (2)

Multiplying eq1 by 3 and eq2 by 7 and subtracting eq2 from eq1.

⇒ 3(7a + 6b) - 7(3a + 5b) = 3(3800) - 7(1750)

⇒ 21a + 18b – 21a – 35b = 11400 – 12250

⇒ -17b = - 850

⇒ 17b = 850

⇒ b = 50

Putting this in eq 1, we get

7a + 6(50) = 3800

⇒ 7a + 300 = 3800

⇒ 7a = 3500

⇒ a = 500

Hence,

Each bat cost a = 500 Rupees and Each ball costs b = 50 Rupees.