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The co-ordinates of a point P in 1 pointquadrant I are (8,y). If thedistance of P from origin is 10units, then the value of y isO 2 unitsO 4 uniteO6 unitsO 8units |
Answer»
We know : In FIRST quadrant, both x and y co-ordinate are positive Hence y will have a positive value ________________________________________________________ Distance Between Two Points is given by : Note : The Distance of Point P(x₁ , y₁) from Origin O(0,0) is OP = Coming to Question : OP = ⇒ 10 units = ⇒ 10 units = ⇒ 10 units = Squaring On Both Sides ⇒ (10)² units = ⇒ 100 units = 64 + y² Subtracting 64 from Both Sides ⇒ 100 units - 64 = 64 + y² - 64 ⇒ 36 units = y² Switch Sides ⇒ y² = 36 units Taking Root on Both Sides ⇒ √y² = ±√36 units ⇒ y = ±√36 units ⇒ y = + 6 units or - 6 units We already came to know y will have a positive value ⇒ y = 6 units
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