The CO in a 20L sample of gas was converted to CO_2 by passing the gas over iodine pentoxide heated to 150^@C: I_2O_5(s)+5CO(g)to5CO_2(g)+I_2(g) The iodine distilled at this temperature and was collected in an absorber containing 10 mL of 0.011 M Na_2S_2O_3.The excess hypo was back titrated with 5 mL of 0.001 M I_2 solution. What must be the milligrams of Co in 1 L of the original gas sample ?

The CO in a 20L sample of gas was converted to CO_2 by passing the gas

1.	The CO in a 20L sample of gas was converted to CO_2 by passing the gas over iodine pentoxide heated to 150^@C: I_2O_5(s)+5CO(g)to5CO_2(g)+I_2(g) The iodine distilled at this temperature and was collected in an absorber containing 10 mL of 0.011 M Na_2S_2O_3.The excess hypo was back titrated with 5 mL of 0.001 M I_2 solution. What must be the milligrams of Co in 1 L of the original gas sample ?
Answer» 0.35 MG 0.70 mg 0.07 mg 3.5 mg Solution :MEQ of `l_2` LIBERATED =10 X 0.011 x 1-5 x 0.001 x 2=0.1 Millimoles of CO=`0.1/2 XX5 =0.25` Weight of CO in 1L =`0.25/20xx28 =0.35 mg`