The CO in a 20L sample of gas was converted to CO_2 by passing the gas over iodine pentoxide heated to 150^@C: I_2O_5(s)+5CO(g)to5CO_2(g)+I_2(g) The iodine distilled at this temperature and was collected in an absorber containing 10 mL of 0.011 M Na_2S_2O_3.The excess hypo was back titrated with 5 mL of 0.001 M I_2 solution. What is the weight (in mg) of iodine produced due to the reaction with I_2O_5(s) when it reacted with CO(g) in 20L sample of gas ?

The CO in a 20L sample of gas was converted to CO_2 by passing the gas

1.	The CO in a 20L sample of gas was converted to CO_2 by passing the gas over iodine pentoxide heated to 150^@C: I_2O_5(s)+5CO(g)to5CO_2(g)+I_2(g) The iodine distilled at this temperature and was collected in an absorber containing 10 mL of 0.011 M Na_2S_2O_3.The excess hypo was back titrated with 5 mL of 0.001 M I_2 solution. What is the weight (in mg) of iodine produced due to the reaction with I_2O_5(s) when it reacted with CO(g) in 20L sample of gas ?
Answer» 6.35 MG 127 mg 12.7 mg 0.635 mg Solution :WEIGHT of `I_2=0.1/2xx(2xx127)=12.7 mg`