The class mark of a particular class in a continuous frequency distrib

1.	The class mark of a particular class in a continuous frequency distribution is25 and class size is 10. Find the class interval
Answer» Answer: Let LOWER Limit be L ∴ Upper Limit =L+10 [ SINCE, Class Width =10] Now, we know that ClassMark=(LowerLimit+UpperLimit)÷2 ∴ (L+L+10)÷2=25 [Class MARK 25 given] ⇒ 2L+10=50 ⇒ 2L=40 ⇒ L=20 ∴ Lower Limit of the class =20 Upper Limit of the class =20+10=30 The required class is 20−30

The class mark of a particular class in a continuous frequency distribution is25 and class size is 10. Find the class interval

Answer»

Answer:

Let LOWER Limit be L

∴ Upper Limit =L+10 [ SINCE, Class Width =10]

Now, we know that

ClassMark=(LowerLimit+UpperLimit)÷2

∴ (L+L+10)÷2=25 [Class MARK 25 given]

⇒ 2L+10=50

⇒ 2L=40

⇒ L=20

∴ Lower Limit of the class =20

Upper Limit of the class =20+10=30

The required class is 20−30

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The class mark of a particular class in a continuous frequency distribution is25 and class size is 10. Find the class interval​

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The class mark of a particular class in a continuous frequency distribution is25 and class size is 10. Find the class interval