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The circuit shown below contains two ideal diodes, each with a forward resistance of 50Ω. If the battery voltage is 6 V, the current through the 100Ω resistance (in Amperes) is :(1) 0.036(2) 0.027(3) 0.030(4) 0.020 |
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Answer» Correct option (4) 0.020 Explanation: No current flows through diode D2 as it is reverse biased. So, total resistance = 50 + 150 + 100 = 300Ω. Current through 100 Ω resistance I = V/R = 6/300 = 0.02 amp |
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