1.

The circuit shown below contains two ideal diodes, each with a forward resistance of 50Ω. If the battery voltage is 6 V, the current through the 100Ω resistance (in Amperes) is :(1)  0.036(2)  0.027(3)  0.030(4)   0.020

Answer»

Correct option (4)  0.020

Explanation:

No current flows through diode D2 as it is reverse biased. So, total resistance = 50 + 150 + 100 = 300Ω.

Current through 100 Ω resistance I = V/R = 6/300 = 0.02 amp



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