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The circle passing through the point (-1,0) and touching the y-axis at (0,2) also passes through the point:A. `( -3//2,0)`B. `(- 5//2,2)`C. `(-3//2,5//2)`D. `(-4,0)` |
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Answer» Correct Answer - D Equation of circle touching the y-axis at (0,2) is `(x-0)^(2)+(y-2)^(2)+lambdax =0` It passes through `(-1,0)` . Therefore, `1+4-lambda =0` or `lambda =5` `:. `Equation of circle is `x^(2)+y^(2)+5x-4y+4=0` Putting `y=0` , we get ` x= -1,-4` Therefore, the circle passes through `(-4,0)` |
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