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The chords AB and CD of a circle intersect at. If MA = 6 cm, MB = 8 cm and CD = 16 cm. Find MC and MD. |
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Answer» CD = 16 centimetre MC = 8 – x, MD = 8 + x then, MA x MB = MC x MD 6 x 8 = (8 – x)(8 + x) 48 = 64 – x2 , x2 = 16, x = 4 MC = 8 – 4 = 4 centimetre MD = 8 + 4 = 12 centimetre |
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