1.

The chords AB and CD of a circle intersect at. If MA = 6 cm, MB = 8 cm and CD = 16 cm. Find MC and MD.

Answer»

CD = 16 centimetre MC = 8 – x, MD = 8 + x

then, MA x MB = MC x MD

6 x 8 = (8 – x)(8 + x)

48 = 64 – x2 , x2 = 16, x = 4

MC = 8 – 4 = 4 centimetre

MD = 8 + 4 = 12 centimetre



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