1.

The chord of contact of (1,2) with respect to the circle x^2+y^2-4x-6y+2=0​

Answer»

S↪Actually WELCOME to the CONCEPT of the CIRCLES...

↪Basically we know that ..

↪CHORD OF CONTACT IS GIVEN BY

↪T=0

↪such that equation of tangent = 0

↪therefore

↪xx1 + yy1 + G (x+x1) + F (y+y1) + c =0

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