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The choice of a reducing agent in a particular case depends on thermodynamic factor. How far do you agree with this statement? Support your opinion with example. |
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Answer» Solution :The STATEMENT is correct. We CONSIDER the relation : `DeltaG=DeltaH-TDeltaS` `DeltaG^(@)=-RTlnK` For a PARTICULAR reducing AGENT to work with a metallic oxide. Example : The VALUE of `DeltaG` should be negative. |
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