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The chlorate ion can disproportinate in basic according to reaction 2ClO_3^(-) hArr ClO_2^(-) +ClO_4^(-) calculate the value of equilibrium constant. Given E_(ClO_4^(-)//ClO_3^(-))^@=0.36 V and E_(ClO_3^(-)//ClO_2^(-))^@ =0.33 V at 298 K : -

Answer»

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Solution :`E_"CELL"^@=E_(ClO_3^(-)//ClO_2^(-))^@ +E_(ClO_3^(-)//ClO_4^(-))^@`
=0.33-0.36=-0.03 V
`E_"cell"^@=0.06/n ` LOG K
-0.03 = `0.06/2` log K
`K=10^(-1)` = 0.1 M


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