The charge required for the reduction of 1 mole of MnO_(4)^(-)to MnO_( – InterviewSolution

1.	The charge required for the reduction of 1 mole of MnO_(4)^(-)to MnO_(2) is
Answer» 1 F 3 F 5 F 7 F Solution :`overset(+7)MnO_4^(-)+3E^(-)rarroverset(+4)MnO_2` 3F charge will be required to refuse 1 MOLE of `MnO_4 ` to `MnO_2`.

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