1.

The charge required for the reduction of 0.4 mol of K_2Cr_2O_7 toCr^(3+) ions is

Answer»

0.6 F
` 2.4 xx 96500 C `
`6 xx 96500 C `
` 12.4 xx 96500 F `

SOLUTION :`K_2Cr_2 O_7 to Cr^(+3) ,` For 1 mole ` to6 xx 96500 c `, 0.4 mole ` to?`
`(0.4 xx 6 xx 96500)/(1) = 2.4 xx 96500`


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