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The charge of an electron is 1.6 into 10 to the power minus 19 coulomb find the number of electrons that will flow per second to constitutea current of 2 ampere |
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Answer» Answer: 6.25x10^18 Charge (Q) = 1 C (Given) Electron (e) = 1.6× 10^-19 (Given) Number of electron (n) = We need to find Now, 1C/s= 1 ampere. Suppose n ELECTRONS MAKE 1C. Then, = ne /s= 1 ampere Solving by unitary METHOD, where - Q = ne Therefore, n=1(ampere)/(1.6x10^-19)C = 0.625x10^19/s = 6.25x10^18 Thus, 6.25x10^18 electrons per second should pass through a conductor in 1 second to CONSTITUTE 1 ampere of current. |
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