1.

The change of energy on freezing 1.00kg of liquid water at 0^(@)C A0.001 molal solution of [Pt(NH_(3))_4 CI_4] in water had a freezing point depression of 0.005 4^(@)C.If K_(f) for water is 1.80, the correct formulation for the above molecule is

Answer»

`[Pt(NH_(3))_(4)CI_(3)]CI`
`[Pt(NH_(3))_(4)CI_(2)]CI_(2)`
`[Pt(NH_(3))_(4)CI]CI_(3)`
`[Pt(NH_(3))_(4)CI_(4)]`

Solution :`DELTA T_(F)= imk_(f), 0.0054=ixx1.8xx0.001`
i=3 so it is `[Pt(NH_(3))_(4)Cl_(2)]Cl_(2)`.


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