1.

The change is entropy for the fusion of 1 mole of ice is [M.P of ice = 273 K molar, enthalpy of fusion for ice = 60 kJ mol^(-1)]

Answer»

`11.73 JK^(-1) MOL^(-1)`
`18.84 JK^(-1) mol^(-1)`
`219.7 JK^(-1) mol^(-1)`
`24.47 JK^(-1) mol^(-1)`

Solution :Entropy change of fusion
`DeltaS_(f)=(DeltaH_(f))/(T)`
`DeltaH_(f)=60XX10^(3)J mol^(-1), T=273 K`
`DeltaS_(f)=(60xx10^(3))/(273)=219.7 J K^(-1)mol^(-1)`.


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