The change in the internal energy of a given reaction at 300 K is -908 kjoule mole⁻¹, then calculate its enthalpy change. 4NH₃ (g) + 5O₂ (g) --> 6H₂O (g) + 4NO (g) (R = 8.314 joule)

The change in the internal energy of a given reaction at 300 K is -908

1.	The change in the internal energy of a given reaction at 300 K is -908 kjoule mole⁻¹, then calculate its enthalpy change. 4NH₃ (g) + 5O₂ (g) --> 6H₂O (g) + 4NO (g) (R = 8.314 joule)
Answer» reaction in which two DIFFERENT IONS or a group of ATOMS in the reactant MOLECULES are DISPLACED by each other is called double displacement Explanation:Na2So4+BaCl2 gives BaSo4+2NaCl