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The centre of the smallest circle touching the circles `x^2+ y^2-2y -3=0` and `x^2 +y^ 2-8x -18y +93= 0` is:A. (3,2)B. (4,4)C. (2,5)D. (2,7) |
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Answer» Correct Answer - 3 Circles `S_(1) : x^(2)+y^(2)-2y-3=0` and `S_(2) : x^(2)+y^(2)-8x-18y+93=0` `C_(1) -= (0,1)` and `r_(1)=2` `C_(2) -= (4,9)` and `r_(2)=2` Since circles have same radius , centre `C_(3)` of the smallest circle is collinear with `C_(1)` and `C_(2)` and is midpoint of `C_(1)C_(2)`. `:. C_(3) -= (2,5)` |
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