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The centre of circleinscribed in a square formed by lines `x^2-8x+12=0a n dy^2-14 y+45=0`is`(4,7)``(7,4)``(9,4)``(4,9)`A. (4, 7)B. (7, 4)C. (9, 4)D. (4, 9) |
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Answer» Correct Answer - A The equation of the sides of the square are `x=2, x=6, y=5` and `y=9`. Therefore, the coordinates of the end points of a diameter are (2, 5) and (6, 9). So, the centre of the square has the coordinates `((2+6)/(2), (5+9)/(2))=(4, 7)`. Hence, the coordinates of the centre of the circle are (4, 7). |
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