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The centre of a circle is (2a, a-7). Find the value (s) of a, if the circle passes through the(11, -9) and has diameter 10 V2 units. |
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Answer» Diameter is 10√2then radius =5√2 √(2a-11)²+(a-7+9)²=5√2(2a-11)²+(a+2)²=(5√2)²4a²-44a+121+a²+4a+4=505a²-40a+75=0a²-8a+15=0(a-3)(a-5)=0a=3,5 |
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