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The center angle of the circle is 60 ° and the diameter is 6 cm. Draw this circle. Draw a circle touching this circle and the arc,with whole exeplention |
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Answer» Solution : For semicircle with diameters PS, Radius = 6 cm ∴ Area of such semicircle =12πr2=12×227×62=3967cm2 Diameter PS=6+6=12cm ∴PQ=QR=RS=4cm For semicircle with diameter QS, radius = 4 cm ∴ Its area =12πr2=12×227×42=1767cm2 For semicircle with diameter PQ, radius = 2 cm ∴ Its area =12×227×22=447cm2 ∴ Area of shaded region =3967−1767+447=2647=37.71cm2 Given: PS = diameter of circle and radius (R) = 6 cm diameter PS=2×r ⇒PS=2×6 PS=12cm PQ=QR=RS=123=4cm each. Hence, REQUIRED perimeters = circumference of semicircle with radius 6 cm + circumference of semicircle with radius 4 cm + circumference of semicircle with radius 2 cm. 6π+4π+2π=12πcm |
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