1.

The cell, Zn|Zn^(2+)(1M)||Cu^(2+)(1M)|Cu,(E_(cell)=1.10V), was allowed to be completely discharged at 298K. The realtive concentration of Zn^(2+) to Cu^(2+),((Zn^(2+)])/([Cu^(2+)])) is

Answer»

`9.65xx10^(4)`
antilog 24.08
`37.3`
`10^(37.3)`

Solution :The cell reaction is: `Zn+CU^(2+)toZn^(2+)+Cu` when the cell is COMPLETELY discharged, `E_(cell)^(@)=(0.0591)/(2)"LOG"([Zn^(2+)])/([Cu^(2+)])`
i.E., `1.10=(0.591)/(2)"log"([Zn^(2+)])/([Cu^(2+)])`
or `([Zn^(2+)])/([Cu^(2+)])=37.3` or `([Zn^(2+)])/([Cu^(2+)])=10^(37.3)`


Discussion

No Comment Found