1.

The cell Zn | Zn^(2+)(1 M)||Cu^(2+)(1 M)|Cu E_("cell")^(@)=1.10 Vwas allowed to be copletely discharged at 298 K The relative concentration of (Zn^(2+))/(Cu^(2+)) is

Answer»

antilog (24.08)
37.2
`10^(37.2)`
`9.65xx10^(4)`

Solution :Celliscompletelydischarged it meanswhenequilibriumgetsestablished `E_(cell) =0`
`ZN|Zn^(2+) (1M)||CU^(2+)(1 M)|Cu`
`k_(eq)=[(Zn^(2+))]/[(Cu^(2+))]`
`log k_("eq") =(E_("cell")^(@))/(0.591)=(2xxx1.1)/(0.591)=37.2`
`k_("eq") =10^(37.2)`


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