1.

The cell Pt, H_(2) (1atm) H^(+) (pH =x)| Normal calomel Electrode has an EMF of 0.67V at 25^(@)C .Calculate the pH of the solution. The oxidation potential of the calomel electrode on hydrogen scale is -0.28V.

Answer»


Solution :`E_(CELL) = E_(cell)^(@) -(0.0591)/(1)log 10^(-x)`
`0.67 =0.28 +(0.0591)/(1) XX x`
`x = 6.61`


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