1.

The cell potential E_("cell") is ______

Answer»

`E_("cell")^(@)=E_("CATHODE")^(@)-E_("anode")^(@)`
`E_("cell")^(@)=E_("anode")^(@)-E_("cathode")^(@)`
`E_("cell")^(@)=E_("cell")^(@)-0.0591` LOG K
`E_("cell")-0.0591/n`log K

Answer :D


Discussion

No Comment Found

Related InterviewSolutions