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The ceiling of a long hall is 25m high. What is the maximum horizontal distance that a ball thrown with a speed of 40m/s can go without hitting the ceiling of the hall? |
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Answer» SOLUTION :`H= 25 m u= 40 m//s`, `H=u^2 sin^2 THETA/(2G)` i.e 25 = `(40^2) sin^2 theta / (2xx9.8)` on solving `theta = 33.6^@` and ` R=u^2 sin 2 theta/(g) = (40)^2 sin 2 (33.6)/(9.8)` m= 150.5m |
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