Saved Bookmarks
| 1. |
The ceiling of a long hall is 25 m high. What is the maximum horizontal distance that a ball thrown with a speed of 40 ms can go without hitting the ceiling of the hall. {Don't use calculator for calculating angle. I need steps so the answer is 150.5m} Class 11 |
|
Answer» he ceiling of HALL is 25 m high therefore the max. height attained by the ball will be 25m.i.e. H = 25m, u = 40 m/s [given]we KNOW, H = u2sin2θ / 2gor, sin2θ = 2gH / u2 = 2 X 9.8 x 25 / ( 40 )2 = 0.30625or, sin θ = 0.5534or, θ = 33.6 oTherefore, R = u2sinθ / g = (40)2 sin 67.2o /9.8 = 150.5 mHope it helps..!! |
|