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The cartesian coordinates of a point on the parabola x2 =36y ,whose parameter is 1/3. |
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Answer» Parametric equation of parabola x2 = 36y is (18t, 9t2) ∵ \(t = \frac13\) given ∴ Point on parabola is \(\left(\frac{18}3,\frac99\right) = (6,1)\). Hence, required point is (6, 1). |
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