The calculated spin magnetic moment of Fe(II) is : – InterviewSolution

1.	The calculated spin magnetic moment of Fe(II) is :
Answer» 4.90 B.M. 4.47 B.M. 5.91 B.M. 0 Solution :Fe(II) HAS4 UNPAIRED elecrtrons. `= sqrt(N (n+2)) = sqrt(4(4 +2))` ` = sqrt(24) = 4.90` B.M.

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