1.

The calculated bond order in superoxide ion is :

Answer»

1.5
1
2.5
2

Solution :The bond ORDER of superoxide ion `O_(2)^(-)`is `O_(2)^(-)to sigma1s^(2)sigma^(**)1S^(2)sigma2s^(2)sigma^(**)2S^(2)sigma2p_(Z)^(2)pi2p_(x)^(2)~~pi2p_(y)^(2)pi^(**)3p_(x)^(2)~~pi^(**)2p_(y)^(1)`
Bond oeder `=1//2[N_(b)-N_(a)]`
`=1//2[10-7]=1.5`


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