1.

The C^(14) " to " C^(12) ratio in a wooden article is 13% that of the fresh wood. Calculate the age of the wooden article. Given that the half-life of C^(14) is 5770 years

Answer»

16989 years
16858 years
15675 years
17700 years

Solution :`(N)/(N_(0)) = ((1)/(2))^((T)/(t_(1//2))) rArr (13)/(100) = ((1)/(2))^((T)/(5770))`
Taking LOG `rArr "log" (13)/(100) = (T)/(5770) log 1//2 rArr 16989 yrs`


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